--- Bill Moseley <moseley@hank.org> wrote:

[snip]

> > 159c176
> > <         i = *(unsigned long *) prop->propValue; 
> /* read binary */
> > ---
> > >         i =
> convPropValue2ULong(prop->propValue); /* read binary
> */
> 
> [snip]
> 
> I admit that I'm not 100% clear what the compiler
> should do when
> casting "unsigned char propValue[1]" to "unsigned
> long" -- always
> seems like a bit of magic to me. ;) [snip]

Hello Bill:

The line
  i = *(unsigned long *) prop->propValue;

is probably intended like

 i = * ( (unsigned long *) (prop->propValue) );

Which is to say, cast the (prop->propValue) pointer to
an (unsigned long*) and de-reference it to an unsigned
long.

jrobinson

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